Home
Class 12
PHYSICS
Find out the magnitude of electric field...

Find out the magnitude of electric field intensity and electric potential due to a dipole of dipole moment `vec(P)=hat(i)+sqrt(3)hat(j)` kept at origin at following points.
(i) (2, 0, 0) (ii) `(-1, sqrt(3), 0)`

Text Solution

Verified by Experts

The correct Answer is:
`|vec(E)|=(sqrt(7)K)/8, V=K/4` (ii) `|vec(E)|=(Ksqrt(7))/8, V=K/4`
`["where "K=1//4 pi in_(0)]`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    RESONANCE|Exercise Exercise-1 Section (I)|5 Videos
  • ELECTROSTATICS

    RESONANCE|Exercise Exercise-1 Section (J)|7 Videos
  • ELECTROSTATICS

    RESONANCE|Exercise Exercise-1 Section (G)|7 Videos
  • ELECTROMAGNETIC INDUCTION

    RESONANCE|Exercise A.l.P|19 Videos
  • EXPERIMENTAL PHYSICS

    RESONANCE|Exercise PART -II|10 Videos

Similar Questions

Explore conceptually related problems

The magnitude of electric field intensity at point (2,0,0) due to a dipole of dipole moment, vec P=hat i+sqrt(3)hat j kept at origin is where k=1/4 pi varepsilon_(0) is , (sqrt(m)k)/(n) then n-m is-

The magnitude of electric field intensity at point B(2,0,0) due to dipole of dipole moment, vec(p)=hat(i)+sqrt(3)hat(j) kept at origin is (assume that the point B is at large distance from the dipole and k=(1)/(4pi epsilon_(0)))

The magnitude of electric field intensity at point B(x,0,0) due to a dipole of dipole moment , vec(P) - P_(0) ( hat(i) + sqrt(3)hat(j)) kept at origin is sqrt(n) ((kp_(0))/(r^(3))) , find n (assume that the point is at large distance form the diople , k = (1)/(4 pi in_(0)) .

The electric field intensity vec(E) , , due to an electric dipole of dipole moment vec(p) , at a point on the equatorial line is :

What is the angle between the directions of electric field due to an electric dipole and its dipole moment at any : (i) Axial p oint . (ii) Equatorial point .

The potential field of an electric field vec(E)=(y hat(i)+x hat(j)) is

Find out the electric flux through an area 10 m^(2) lying in XY plane due to a electric field vec(E)=2hat(i)-10 hat(j)+5hat(k) .

Two small electric dipoles each of dipole moment p hati are situated at (0,0,0) and (r,0,0) . The electric potential at a point ((r)/(2),(sqrt(3r))/(2),0) is:

When dipole moment vec(p) of a dipole is parallel to electric field intensity vec(E ) (stable equilibrium) the potential energy of dipole is

An electric dipole of moment overset( r ) (p) = (hat(i) + 2hat ( j )) xx10^(-28) Cm is at origin. The electric field at point ( 2,4) due to the dipole is parallelto