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A simple pendulum has a length l & mass ...

A simple pendulum has a length `l` & mass of bob m. The bob is given a charge q coulomb. The pendulum is suspended in a uniform horizontal electric field of strength E as shown in figure, then calculate the time period of oscillation when bob is slightly displaced from its mean position.

A

`2pi sqrt(l/g)`

B

`2pi sqrt({l/(g+(qE)/m)})`

C

`2pi sqrt({l/(g-(qE)/m)})`

D

`2pi sqrt(l/sqrt(g^(2)+((qE)/m)^(2)))`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • A simple pendulum has a length l , mass of bob m . The bob is given a charge q .The pendulum is suspended between the vertical plates of charged parallel plate capacitor. If E is the field strength between the plates ,then time period T =

    A
    `2 pi sqrt((l)/(g))`
    B
    `2 pi sqrt({(l)/(g + (qE)/(m))})`
    C
    `2 pi sqrt({(l)/(g - (qE)/(m))})`
    D
    `2 pi sqrt((l)/((g^(2) + ((qE)/(m))^(2))^(1//2)))`

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    A
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    B
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