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Due to an electric dipole shown in fig.,...

Due to an electric dipole shown in fig., the electric field intensity is parallel to dipole axis :

A

at P only

B

at Q only

C

both at P and at Q

D

neither at P nor at Q

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • For an electric dipole potential & electric field

    A
    can have same magnitude for a point at a distance less than 2 meter
    B
    can have same magnitude fo a point at distacnes greater than 2 meter
    C
    can never be equal
    D
    can never be predicted

  • An electric dipole moment p is placed in an electric field of intensity 'E' . The dipole acquires a position such that the axis of the dipole makes an angle theta with the direction of the field. Assuming that the potential energy of the dipole to be zero when theta= 90^(@) , the torque and the potential energy of the dipole will respectively be

    A
    `pE cos theta, - pE sin theta`
    B
    `pE sin theta, - pE cos theta`
    C
    `pE sin theta, - 2pE cos theta`
    D
    `pE sin theta, 2pE cos theta`

  • An electric dipole is placed in uniform electric field. The magnitude of electric dipole moment of dipole is p and external electric field intensity is E. Asume theta is the angle between electric dipole moment and electric field intensity and U represents potential energy of electric dipole

    A
    If U=0 for `theta=0` then for other orientations `U=pE (1-cos theta)`
    B
    If U=0 for `theta=90^@` then for other orientations `U=-pE cos theta`
    C
    If U=0 for `theta=180^@` then for other orientations `U=-pE (1+cos theta)`
    D
    All of the above

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