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A 1000kg rocket is set for vertical firi...

A 1000kg rocket is set for vertical firing. The exhaust speed is `500m//s`.To give the rocket an initial upward acceleration of `30 m//s^(2)`, the amount of gas ejected per second to supply the needed thrust is

A

80 kg `//` sec

B

40 kg `//` sec

C

30 kg `//` sec

D

10 kg `//` sec

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The correct Answer is:
To solve the problem, we need to determine the amount of gas (mass) ejected per second (dm/dt) that is required to provide the necessary thrust for the rocket to achieve the desired upward acceleration. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Mass of the rocket (m) = 1000 kg - Exhaust speed (V) = 500 m/s - Upward acceleration (a) = 30 m/s² - Gravitational acceleration (g) = 9.81 m/s² (approximately) 2. **Calculate the Weight of the Rocket:** The weight (W) of the rocket can be calculated using the formula: \[ W = m \cdot g = 1000 \, \text{kg} \cdot 9.81 \, \text{m/s}^2 = 9810 \, \text{N} \] 3. **Determine the Required Thrust Force:** According to Newton's second law, the net force acting on the rocket is given by: \[ F_{\text{net}} = F_{\text{thrust}} - W \] Rearranging this gives: \[ F_{\text{thrust}} = F_{\text{net}} + W \] The net force (F_net) required to achieve the upward acceleration can be calculated as: \[ F_{\text{net}} = m \cdot a = 1000 \, \text{kg} \cdot 30 \, \text{m/s}^2 = 30000 \, \text{N} \] Therefore, the thrust force required is: \[ F_{\text{thrust}} = 30000 \, \text{N} + 9810 \, \text{N} = 39810 \, \text{N} \] 4. **Relate Thrust Force to Mass Ejection Rate:** The thrust force can also be expressed in terms of the exhaust speed and the rate of mass ejection: \[ F_{\text{thrust}} = V \cdot \frac{dm}{dt} \] Substituting the values we have: \[ 39810 \, \text{N} = 500 \, \text{m/s} \cdot \frac{dm}{dt} \] 5. **Solve for the Mass Ejection Rate (dm/dt):** Rearranging the equation to find dm/dt gives: \[ \frac{dm}{dt} = \frac{39810 \, \text{N}}{500 \, \text{m/s}} = 79.62 \, \text{kg/s} \] Rounding this to two decimal places, we get: \[ \frac{dm}{dt} \approx 80 \, \text{kg/s} \] ### Final Answer: The amount of gas ejected per second to supply the needed thrust is approximately **80 kg/s**.
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