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Find the ratio of magnitude of angular m...

Find the ratio of magnitude of angular momentu of a rolling disc about origin to that about the point P on the disc, as shown in the figure.

A

`2:1`

B

`1:1`

C

`1:3`

D

`4:3`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Moment of inetia of a disc about OO' is

    A
    `(3mr^(2))/2`
    B
    `(mr^(2))/2`
    C
    `(5mr^(2))/2`
    D
    `(5mr^(2))/4`

  • A disc of mass M and radius R is rolling with angular speed omega on a horizontal plane. The magnitude of angular momentum of the disc about a point on ground along the line of motion of disc is :

    A
    `(1//2)MR^(2)omega`
    B
    `MR^(2)omega`
    C
    `(3//2)MR^(2)omega`
    D
    `2MR^(2)omega`

  • A disc of a mass M and radius R can rotate freely in vertical plane about a horizontal axis at O . Distant r from the centre of disc as shown in the figure. The disc is released from rest in the shown position. The angular acceleration of disc when OC rotates by an angles of 37^(@) is

    A
    `(8rg)/(5[R^(2)+2r^(2)])`
    B
    `(5rg)/(4[R^(2)+2r^(2)])`
    C
    `(10rg)/(3[R^(2)+2r^(2)])`
    D
    `(8rg)/(5R^(2))`
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