A force F of constant magnitude acts on a block of mass 'm' and t=0,initially along positive x-direction. The direction of force F starts rotating with a constant angular velocity `omega` in anticlockwise sense. Then the magnitude of velocity of the block as a function of time 't' is ( initial block was at rest )

Options

A. `(F)/( m omega ) sin ((omegat)/( 2))`
B. `(2F)/( m omega ) sin ((omegat)/( 2))`
C. `(F)/( 2 m omega) sin ((omegat)/( 2))`
D. `(2F)/( 3 m omega) sin ((omegat)/( 2))`

Answer

B