Isopropyl iodine can be prepared by the action of HI on

Options

A. Propane
B. Propene
C. Isopropyl alcohol
D. Glycerol

Answer

To prepare isopropyl iodine (CH3-CH(I)-CH3) through the action of hydroiodic acid (HI), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Starting Material**:
We need a suitable starting material that can react with HI to form isopropyl iodine. The most appropriate starting material is propene (CH3-CH=CH2), which is an unsaturated hydrocarbon.

**Hint**: Look for a compound that has a double bond, as it will react with HI.

2. **Reaction with Hydroiodic Acid**:
When propene reacts with HI, the reaction proceeds via electrophilic addition. The hydrogen ion (H+) from HI will first add to one of the carbon atoms in the double bond.

**Hint**: Remember that H+ will add to the carbon that leads to the most stable carbocation.

3. **Formation of Carbocation**:
The addition of H+ to propene leads to the formation of a carbocation. The more stable secondary carbocation (CH3-CH^+-CH3) is formed because it is stabilized by the two methyl groups.

**Hint**: Consider the stability of carbocations; tertiary > secondary > primary.

4. **Nucleophilic Attack by Iodide Ion**:
The iodide ion (I-) from HI will then attack the positively charged carbon of the carbocation, resulting in the formation of isopropyl iodide (CH3-CH(I)-CH3).

**Hint**: Nucleophiles attack positively charged centers; in this case, I- attacks the carbocation.

5. **Final Product**:
The final product of this reaction is isopropyl iodine, which is the desired compound.

**Hint**: Verify the structure of the product to ensure it matches isopropyl iodine.

### Summary:
Isopropyl iodine can be prepared by the action of HI on propene, where HI adds across the double bond, forming a carbocation that is subsequently attacked by iodide ion to yield isopropyl iodine.