Consider the following reactions:
`MX_(4)+X'_(2) to MX_(4)X_(2)'`
If atomic number of M is 52 and X and X' are halogens and X' is more electonegative than X. The choose correct statemetn regarding given information:

Options

A. Both X' atoms occupy axial positions which are formed by overlaping of p and d-orbitals only
B. All M-X bond lengths are identical in both `MX_(4) and MX_(4)X'_(2)` compounds
C. Central atom 'M' does not use anyone valence non-axial set of d-orbitals in hybridization of final product
D. Hybridization of central atom 'M' remains same in both reactant and final product

Answer

C

Explanation

`MX_(2)+X._(2) to MX_(4)X._(2)` (M=Te)
`to` Hybridisation of `Te: sp^(3)d^(2)(sp_(x)p_(y)p_(z)d_(x^(2)-y^(2))d_(x^(2)))`
`to` Axial position are formed by hybrid orbitals
`to` All M-X bond lengths are identical
`to` Hybridisation of `Te: sp^(3)d(sp_(x)p_(y)+p_(x)d_(x^(2)))`
``to` All M-X bond lengths are not identical