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If E.A.N. of central metal cation M^(2+)...

If E.A.N. of central metal cation `M^(2+)` in a non-chelating complex is 36 and atomic no. of metal M is 26, then the number of monodentate ligand is in this complex are:

A

5

B

4

C

6

D

none of these

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The correct Answer is:
To solve the problem step by step, we will use the Effective Atomic Number (EAN) formula. The EAN is calculated using the following formula: \[ \text{EAN} = Z - n + 2x \] Where: - \( Z \) = Atomic number of the metal - \( n \) = Charge on the metal ion - \( x \) = Number of monodentate ligands Given: - EAN = 36 - Atomic number of metal \( M \) = 26 - Charge on metal \( M^{2+} \) = +2 ### Step 1: Write down the EAN formula Using the EAN formula: \[ \text{EAN} = Z - n + 2x \] ### Step 2: Substitute known values Substituting the known values into the formula: \[ 36 = 26 - 2 + 2x \] ### Step 3: Simplify the equation Now simplify the equation: \[ 36 = 26 - 2 + 2x \] \[ 36 = 24 + 2x \] ### Step 4: Isolate the term with \( x \) Now, isolate \( 2x \): \[ 36 - 24 = 2x \] \[ 12 = 2x \] ### Step 5: Solve for \( x \) Now, divide both sides by 2 to find \( x \): \[ x = \frac{12}{2} \] \[ x = 6 \] ### Conclusion The number of monodentate ligands in the complex is **6**. ---
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