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If ratio of the roots of the quadratic equation `3m^2x^2+m(m-4)x+2=0` is `lamda` such that `lamda+1/lamda=1` then least value of `m` is (A) `-2-2sqrt3` (B) `-2+2sqrt3` (C) `4+3sqrt2` (D) `4-3sqrt2`

A

`2 - sqrt(3)`

B

`4 - 3sqrt(2)`

C

`-2 + sqrt(2)`

D

`4 - 2sqrt(3)`

Text Solution

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The correct Answer is:
B
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