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If the sum of the deviations of 50 obser...

If the sum of the deviations of 50 observations from 30 is 50, then the mean of these observations is

A

50

B

51

C

30

D

31

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To find the mean of the 50 observations given that the sum of the deviations from 30 is 50, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Deviations**: The deviation of each observation from 30 can be expressed as \( x_i = a_i - 30 \), where \( a_i \) is the \( i^{th} \) observation. 2. **Sum of Deviations**: The problem states that the sum of the deviations from 30 is 50. Mathematically, this can be expressed as: \[ \sum_{i=1}^{50} (a_i - 30) = 50 \] 3. **Expanding the Sum**: We can expand the sum: \[ \sum_{i=1}^{50} a_i - \sum_{i=1}^{50} 30 = 50 \] Since there are 50 observations, we have: \[ \sum_{i=1}^{50} a_i - 30 \times 50 = 50 \] 4. **Calculating the Total Sum**: Simplifying the equation gives: \[ \sum_{i=1}^{50} a_i - 1500 = 50 \] Adding 1500 to both sides results in: \[ \sum_{i=1}^{50} a_i = 1550 \] 5. **Finding the Mean**: The mean \( \bar{a} \) of the observations is calculated as: \[ \bar{a} = \frac{\sum_{i=1}^{50} a_i}{50} = \frac{1550}{50} = 31 \] ### Conclusion: The mean of the observations is **31**.
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