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If `f(x)` satisfies the condition of Rolle's theorem in `[1,2]`, then `int_1^2 f'(x) dx` is equal to (a) 1 (b) 3 (c) 0 (d) none of these

A

`1`

B

`3`

C

`0`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
As `f(x)` satisfies the conditions of Rolle's theorem in `[1,2]`
`f(x)` is continuous in the interval and `f(1)=f(2)`.
Therefore `int_(1)^(2) f'(x)dx=[f(x)]_(1)^(2)=f(2)-f(1)=0`
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