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`T h ev a l u eoft h ed efin i t ein t egr a lint_0^(pi/2)(sin5x)/(sinx)dxi s` 0 (b) `pi/2` (c) `pi` (d) `2pi`

A

`0`

B

`(pi)/2`

C

`pi`

D

`2pi`

Text Solution

Verified by Experts

The correct Answer is:
A
`sin nx-sin(n-2)x=2 cos (n-1)x sinx `
or `int(sin nx)/(sin x)dx=int2cos(n-1)dx+int(sin(n-2)x)/(sinx)dx`
`:. int_(0)^(pi//2) (sin 5x)/(sinx)dx=int_(0)^(pi//2) 2 cos4xdx+int_(0)^(pi//2) (sin3x)/(sinx) dx`
`=0+int_(0)^(pi//2)(sin 3x)/(sin x) dx`
`=int_(0)^(pi//2) dx`
`=(pi)/2`
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