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Arrhenius studied the effect of tempera...

Arrhenius studied the effect of temperature on the rate of a reaction and postulated that rate constant varies with temperture exponentially as `K=A.e^(-Ea//RT)`. This method is generally used for finding the activation energy of reaction . Keeping temperature constant , effect of catalyst on activation energy has also been studied.
If the rate of reaction double for rise of temperature from 500K to 1000K, the activation energy of the reaction will be approximately [ln2=0.7]

A

1.2 kcal/mole

B

1.4 kcal / mole

C

1.8 kcal / mole

D

2.4 kcal/ mole

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The correct Answer is:
B
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Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. If the rate of reaction doubles for 10^(@)C rise of temperature form 290K to 300K, the activation energy of the reaction will be approximately :

Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. If x is the fraction of molecules having energy greater than E_(a) it will be given by :

Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. The pre-exponetial factor in the Arrhenius equation of a first order reaction has the unit :

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