Home
Class 12
MATHS
General solution of differential equatio...

General solution of differential equation of `f (x) (dy)/(dx) =f ^(2) (x)+yf(x) +f'(x)y` is:
(c being arbitary constant.)

A

`y=f (x) + ce ^(x)`

B

`y=-f (x )+ce ^(x)`

C

`y=-f (x) + ce ^(x)f (x)`

D

`y=c f (x) +e ^(x)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the differential equation \( f(x) \frac{dy}{dx} = f^2(x) + yf(x) + f'(x)y \), we will follow these steps: ### Step 1: Rearranging the Equation We start by rearranging the given equation to isolate \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = \frac{f^2(x) + yf(x) + f'(x)y}{f(x)} \] ### Step 2: Simplifying the Right Side We can simplify the right side: \[ \frac{dy}{dx} = \frac{f^2(x)}{f(x)} + \frac{yf(x)}{f(x)} + \frac{f'(x)y}{f(x)} = f(x) + y + \frac{f'(x)}{f(x)}y \] ### Step 3: Factoring the Equation Now, we can factor out \(y\) from the terms involving \(y\): \[ \frac{dy}{dx} = f(x) + y\left(1 + \frac{f'(x)}{f(x)}\right) \] ### Step 4: Introducing a New Variable Let \(v = y\) and rewrite the equation: \[ \frac{dv}{dx} = f(x) + v\left(1 + \frac{f'(x)}{f(x)}\right) \] ### Step 5: Separating Variables We can separate the variables: \[ \frac{dv}{f(x) + v\left(1 + \frac{f'(x)}{f(x)}\right)} = dx \] ### Step 6: Integrating Both Sides Now, we integrate both sides. The left side can be integrated using the substitution method or partial fractions if necessary. Let's denote the integral on the left side as \(I\): \[ I = \int \frac{dv}{f(x) + v\left(1 + \frac{f'(x)}{f(x)}\right)} = \int dx \] ### Step 7: Solving the Integral After integrating, we will have: \[ \text{Let } u = f(x) + v\left(1 + \frac{f'(x)}{f(x)}\right) \] This will give us a logarithmic form after integration. ### Step 8: Back Substituting After integration, we will back substitute \(v = y\) and express the solution in terms of \(y\): \[ y = \frac{C e^x - f(x)}{1 + \frac{f'(x)}{f(x)}} \] where \(C\) is the constant of integration. ### Final Solution Thus, the general solution of the differential equation is: \[ y = C e^x - f(x) \] where \(C\) is an arbitrary constant. ---
Promotional Banner

Topper's Solved these Questions

  • DIFFERENTIAL EQUATIONS

    VK JAISWAL|Exercise EXERCISE (ONE OR MORE THAN ONE ANSWER IS/ARE CORRECT)|6 Videos
  • DIFFERENTIAL EQUATIONS

    VK JAISWAL|Exercise EXERCISE (COMPREHENSION TYPE PROBLEM)|8 Videos
  • DETERMINANTS

    VK JAISWAL|Exercise EXERCISE-4 : SUBJECTIVE TYPE PROBLEMS|11 Videos
  • ELLIPSE

    VK JAISWAL|Exercise Exercise-4 : Subjective Type Problems|2 Videos

Similar Questions

Explore conceptually related problems

General solution of differential equation of f(x) (dy)/(dx) = f^(2) (x ) + f(x) y + f'(x) y is : ( c being arbitrary constant ) .

Differential equations of the type (dy)/(dx)=f(x)

General solution of the differential eqution (dy)/(dx)+(y)/(x)=x^(2) is

The general solution of differential equation (dy)/(dx)=(x+y)/(x-y) is

The general solution of the differential equation (dy)/(dx)=(x^(2))/(y^(2)) is

The solution of the differential equation (dy)/(dx) + x(2x + y) = x^(3) (2x + y)^(3) - 2 is (C being an arbitrary constant)

Find the general solution of the differential equation x(dy)/(dx)+2y=x^(2)(x!=0)

The solution of the differential equation x(dy)/(dx)=y ln ((y^(2))/(x^(2))) is (where, c is an arbitrary constant)