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In a right triangle ABC, right angled at A, on the leg AC as diameter, a semicircle is described. The chord joining A with the point of intersection D of the hypotenuse and the semicircle, then the length AC equals to

A

`(AB*AB)/(sqrt(AB^(2)+AB^(2)))`

B

`(AB*AD)/(AB+AD)`

C

`sqrt(AB*AD)`

D

`(AB*AD)/(sqrt(AB^(2)-AD^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
D
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