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Let A(3, 7) and B(6, 5) are two points. ...

Let A(3, 7) and B(6, 5) are two points. `C:x^(2)+y^(2)-4x-6y-3=0` is a circle.
Q. If O is the origin and P is the center of C, then absolute value of difference of the squares of the lengths of the tangents from A and B to the circle C is equal to :

A

`(AB)^(2)`

B

`(OP)^(2)`

C

`|(AP)^(2)-(BP)^(2)|`

D

`(AP)^(2)+(BP)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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