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cos2 alpha-cos3alpha-cos4alpha+cos5alpha...

`cos2 alpha-cos3alpha-cos4alpha+cos5alpha` simplifies to :

A

`-4"sin"(alpha)/(2)sin alpha "cos"(7alpha)/(2)`

B

`4"sin"(alpha)/(2) sin alpha "cos"(7alpha)/(2)`

C

`-4"sin"(alpha)/(2)"sin"(7alpha)/(2)cos alpha`

D

`-4sin alpha "cos"(alpha)/(2)"sin"(7alpha)/(2)`

Text Solution

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The correct Answer is:
A
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