On reaction of ozone with hydrogen peroxide if we start with one volume of ozone. How many volumes of oxygen will form?

Options

A. 1 volume
B. 0.5 volume
C. 1.5 volume
D. 2 volume

Answer

To solve the problem of how many volumes of oxygen will form when one volume of ozone reacts with hydrogen peroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Write the Chemical Reaction**:
The reaction between ozone (O₃) and hydrogen peroxide (H₂O₂) can be represented as:
\[ 2 \, \text{O}_3 + \text{H}_2\text{O}_2 \rightarrow 2 \, \text{O}_2 + 2 \, \text{H}_2\text{O} \]

2. **Identify the Stoichiometry**:
From the balanced equation, we see that 2 moles of ozone produce 2 moles of oxygen. This means that for every mole of ozone consumed, 1 mole of oxygen is produced.

3. **Volume Relationship**:
According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, the volume of gas produced is directly proportional to the number of moles.

4. **Calculate the Volume of Oxygen Produced**:
If we start with 1 volume of ozone (O₃), based on the stoichiometry from the balanced equation:
\[ 1 \, \text{volume of O}_3 \rightarrow 1 \, \text{volume of O}_2 \]
However, since the reaction produces 2 moles of oxygen for every 2 moles of ozone, we actually get:
\[ 1 \, \text{volume of O}_3 \rightarrow 2 \, \text{volumes of O}_2 \]

5. **Final Conclusion**:
Therefore, if we start with 1 volume of ozone, we will produce **2 volumes of oxygen**.

### Answer:
The answer is **2 volumes of oxygen**.

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