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Which of the following molecule/species ...

Which of the following molecule/species is having minimum number of lone pair on its central atom?

A

`BrF_3`

B

`BrF_(4)^(-)`

C

`XeF_(5)^(+)`

D

`I_(3)^(-)`

Text Solution

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The correct Answer is:
To determine which molecule or species has the minimum number of lone pairs on its central atom, we will analyze the lone pairs present in each of the given species. ### Step-by-Step Solution: 1. **Identify the Central Atom**: - For each molecule, identify the central atom. - Examples: - In BrF3, the central atom is Bromine (Br). - In BrF4-, the central atom is also Bromine (Br). - In XeF5+, the central atom is Xenon (Xe). - In I3-, the central atom is Iodine (I). 2. **Count Valence Electrons**: - Determine the number of valence electrons for the central atom. - Bromine (Br) has 7 valence electrons. - Xenon (Xe) has 8 valence electrons. - Iodine (I) has 7 valence electrons. 3. **Account for Bonds**: - Count the number of bonds formed with surrounding atoms. - For BrF3: Bromine forms 3 bonds with Fluorine (3 electrons used). - For BrF4-: Bromine forms 4 bonds with Fluorine (4 electrons used) and gains an extra electron due to the negative charge. - For XeF5+: Xenon forms 5 bonds with Fluorine (5 electrons used) and loses an electron due to the positive charge. - For I3-: Iodine forms 2 bonds with Iodine atoms and has a negative charge, which adds an electron. 4. **Calculate Lone Pairs**: - Use the formula: \[ \text{Lone pairs} = \frac{\text{Valence electrons} - \text{Number of bonds}}{2} \] - For BrF3: \[ \text{Lone pairs} = \frac{7 - 3}{2} = 2 \] - For BrF4-: \[ \text{Lone pairs} = \frac{8 - 4}{2} = 2 \] - For XeF5+: \[ \text{Lone pairs} = \frac{8 - 5}{2} = 1.5 \text{ (round down to 1)} \] - For I3-: \[ \text{Lone pairs} = \frac{8 - 2}{2} = 3 \] 5. **Compare the Lone Pairs**: - BrF3: 2 lone pairs - BrF4-: 2 lone pairs - XeF5+: 1 lone pair - I3-: 3 lone pairs 6. **Conclusion**: - The species with the minimum number of lone pairs on its central atom is **XeF5+**, which has 1 lone pair. ### Final Answer: **XeF5+ has the minimum number of lone pairs on its central atom.**
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