Which one among the following is the mild oxdizing agent?

Options

A. `CrO_(2)Cl_(2)`
B. `K_(2)Cr_(2)O_(7)`
C. `KMnO_(4)`
D. `HNO_(3)`

Answer

To determine which of the given compounds is a mild oxidizing agent, we will analyze the oxidation states of the compounds provided in the options.

### Step-by-Step Solution:

1. **Understanding Oxidizing Agents**:
- Oxidizing agents are substances that can accept electrons from other substances, thereby oxidizing them. The strength of an oxidizing agent is often related to its oxidation state; a higher oxidation state typically indicates a stronger oxidizing agent.

2. **Analyzing Each Option**:
- **Option 1: CrO2Cl2**
- To find the oxidation state of chromium (Cr) in CrO2Cl2:
- Let the oxidation state of Cr be \( x \).
- The equation based on the oxidation states is:
\[ x + 2(-2) + 2(+1) = 0 \quad \text{(since the compound is neutral)} \]
\[ x - 4 + 2 = 0 \implies x = +6 \]
- Thus, the oxidation state of Cr is +6.

- **Option 2: K2Cr2O7 (Potassium Dichromate)**
- The oxidation state of Cr in K2Cr2O7:
- The equation is:
\[ 2(+1) + 2x + 7(-2) = 0 \]
\[ 2 + 2x - 14 = 0 \implies 2x - 12 = 0 \implies x = +6 \]
- The oxidation state of Cr is also +6.

- **Option 3: MnO4 (Potassium Permanganate)**
- The oxidation state of Mn in MnO4:
- The equation is:
\[ x + 4(-2) = -1 \quad \text{(since MnO4 is the permanganate ion)} \]
\[ x - 8 = -1 \implies x = +7 \]
- The oxidation state of Mn is +7.

- **Option 4: HNO3 (Nitric Acid)**
- The oxidation state of nitrogen (N) in HNO3:
- The equation is:
\[ +1 + x + 3(-2) = 0 \]
\[ 1 + x - 6 = 0 \implies x = +5 \]
- The oxidation state of N is +5.

3. **Comparing the Oxidation States**:
- From the analysis:
- Cr in CrO2Cl2: +6
- Cr in K2Cr2O7: +6
- Mn in MnO4: +7
- N in HNO3: +5
- The highest oxidation state is +7 (MnO4), indicating it is a strong oxidizing agent.
- Both CrO2Cl2 and K2Cr2O7 have an oxidation state of +6, but K2Cr2O7 is generally considered a stronger oxidizing agent due to its structure and ability to accept electrons.
- HNO3, with an oxidation state of +5, is a weaker oxidizing agent.

4. **Conclusion**:
- Among the options, CrO2Cl2 (with an oxidation state of +6) is the mildest oxidizing agent compared to K2Cr2O7 and MnO4, which are stronger oxidizers.

### Final Answer:
**Option 1: CrO2Cl2 is the mild oxidizing agent.**