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Numerically 1 gauss = x tesla, then x is...

Numerically 1 gauss = x tesla, then x is

A

`10^(-4)`

B

`10^(4)`

C

`10^(8)`

D

`10^(-3)`

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The correct Answer is:
To solve the problem of converting gauss to tesla, we need to understand the relationship between these two units of magnetic field strength. ### Step-by-step Solution: 1. **Understand the Units**: - Gauss (G) is a unit of magnetic field strength in the CGS (centimeter-gram-second) system. - Tesla (T) is the SI (International System of Units) unit of magnetic field strength. 2. **Know the Conversion Factor**: - It is known that 1 tesla is equal to 10,000 gauss. This can be expressed mathematically as: \[ 1 \, \text{T} = 10,000 \, \text{G} \] 3. **Convert Gauss to Tesla**: - To find how many tesla is equal to 1 gauss, we can rearrange the conversion factor: \[ 1 \, \text{G} = \frac{1}{10,000} \, \text{T} \] - This can also be expressed in exponential form: \[ 1 \, \text{G} = 10^{-4} \, \text{T} \] 4. **Determine the Value of x**: - From the equation \(1 \, \text{G} = x \, \text{T}\), we can see that: \[ x = 10^{-4} \] 5. **Final Answer**: - Therefore, numerically, \(1 \, \text{gauss} = 10^{-4} \, \text{tesla}\). ### Conclusion: Thus, the value of \(x\) is \(10^{-4}\). ---
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Knowledge Check

  • The interval in which x must lie so that the numerically greatest term in the expansion of (1 - x)^(21) has the numerically greatest coefficient, is

    A
    `[(5)/(6),(6)/(5)]`
    B
    `((5)/(6),(6)/(5))`
    C
    `((4)/(5),(5)/(4))`
    D
    `[(4)/(5),(5)/(4)]`
  • The numerically greatest term in the expansion of (1 + x)^(10) when x = 2//3 , is

    A
    `4^(th)`
    B
    `5^(th)`
    C
    `6^(th) `
    D
    `3^(3d)`
  • Numerically the longest term in the expansion of (3+2x)^(50) , when x=(1)/( 5) is

    A
    `6^(th)`
    B
    `8^(th)`
    C
    `7^(th)`
    D
    None of these
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