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The position x of a particle moving alon...

The position x of a particle moving along x - axis at time (t) is given by the equation `t=sqrtx+2`, where x is in metres and t in seconds. Find the work done by the force in first four seconds

A

Zero

B

2 J

C

4 J

D

8 J

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Rearranging the given equation The position \( x \) of a particle is given by the equation: \[ t = \sqrt{x} + 2 \] We can rearrange this equation to express \( x \) in terms of \( t \): \[ t - 2 = \sqrt{x} \] Now, squaring both sides: \[ (t - 2)^2 = x \] Thus, we have: \[ x = (t - 2)^2 \] ### Step 2: Finding the velocity To find the velocity \( v \), we need to differentiate the position \( x \) with respect to time \( t \): \[ v = \frac{dx}{dt} = \frac{d}{dt}[(t - 2)^2] \] Using the chain rule: \[ v = 2(t - 2) \cdot \frac{d}{dt}(t) = 2(t - 2) \] ### Step 3: Finding initial and final velocities Now we will calculate the initial and final velocities at \( t = 0 \) seconds and \( t = 4 \) seconds. - **Initial velocity** at \( t = 0 \): \[ v_{\text{initial}} = 2(0 - 2) = 2 \times (-2) = -4 \, \text{m/s} \] - **Final velocity** at \( t = 4 \): \[ v_{\text{final}} = 2(4 - 2) = 2 \times 2 = 4 \, \text{m/s} \] ### Step 4: Calculating the initial and final kinetic energy The kinetic energy \( KE \) is given by the formula: \[ KE = \frac{1}{2} mv^2 \] Assuming the mass \( m \) of the particle is \( m \) (we will keep it as a variable since it is not provided): - **Initial kinetic energy**: \[ KE_{\text{initial}} = \frac{1}{2} m (-4)^2 = \frac{1}{2} m \cdot 16 = 8m \, \text{J} \] - **Final kinetic energy**: \[ KE_{\text{final}} = \frac{1}{2} m (4)^2 = \frac{1}{2} m \cdot 16 = 8m \, \text{J} \] ### Step 5: Calculating the work done According to the work-energy theorem, the work done \( W \) is equal to the change in kinetic energy: \[ W = KE_{\text{final}} - KE_{\text{initial}} = 8m - 8m = 0 \, \text{J} \] ### Conclusion The work done by the force in the first four seconds is: \[ \boxed{0 \, \text{J}} \]
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