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A simple pendulum with bob of mass m and...

A simple pendulum with bob of mass m and length x is held in position at an angle `theta_(1)` and then angle `theta_(2)` with the vertical. When released from these positions, speeds with which it passes the lowest postions are `v_(1)&v_(2)` respectively. Then ,`(v_(1))/(v_(2))` is.

A

`(1-cos theta_(1))/(1-cos theta_(2))`

B

`sqrt((1-cos theta_(1))/(1-cos theta_(2)))`

C

`sqrt((2gx(-cos theta_(1)))/(1-cos theta_(2)))`

D

`sqrt((1-cos theta_(1))/(2gx(1-cos theta_(2))))`

Text Solution

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The correct Answer is:
B
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