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If Vectors vec(A)= cos omega hat(i)+ sin...

If Vectors `vec(A)= cos omega hat(i)+ sin omega hat(j)` and `vec(B)=(cos)(omegat)/(2)hat(i)+(sin)(omegat)/(2)hat(j)`are functions of time. Then the value of `t` at which they are orthogonal to each other is

A

`t=0`

B

`t=(pi)/(4omega)`

C

`t=(pi)/(2omega)`

D

`t=(pi)/(omega)`

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The correct Answer is:
D
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