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The initial pressure of COCI2 is 1000 to...

The initial pressure of `COCI_2` is 1000 torr. The total pressure of the system becomes 1500 torr, when the equilibrium `COCI_2(g) hArr CO(g) +CI_2(g)` is attained at constant temperature . The value of `K_p` of a reaction.

A

1500

B

1000

C

2500

D

500

Text Solution

AI Generated Solution

The correct Answer is:
To find the equilibrium constant \( K_p \) for the reaction \( \text{COCl}_2(g) \rightleftharpoons \text{CO}(g) + \text{Cl}_2(g) \), we can follow these steps: ### Step 1: Identify Initial Conditions - The initial pressure of \( \text{COCl}_2 \) is given as 1000 torr. - The initial pressures of \( \text{CO} \) and \( \text{Cl}_2 \) are both 0 torr since they are products formed from the decomposition of \( \text{COCl}_2 \). ### Step 2: Write the Change in Pressure Let \( p \) be the change in pressure of \( \text{COCl}_2 \) that decomposes at equilibrium. Therefore: - At equilibrium, the pressure of \( \text{COCl}_2 \) will be \( 1000 - p \) torr. - The pressure of \( \text{CO} \) will be \( p \) torr. - The pressure of \( \text{Cl}_2 \) will also be \( p \) torr. ### Step 3: Write the Total Pressure at Equilibrium The total pressure at equilibrium is given as 1500 torr. Therefore, we can write the equation: \[ (1000 - p) + p + p = 1500 \] Simplifying this gives: \[ 1000 + p = 1500 \] ### Step 4: Solve for \( p \) Now, we can solve for \( p \): \[ p = 1500 - 1000 = 500 \text{ torr} \] ### Step 5: Determine Partial Pressures at Equilibrium Now that we have \( p \): - The pressure of \( \text{COCl}_2 \) at equilibrium is: \[ 1000 - p = 1000 - 500 = 500 \text{ torr} \] - The pressure of \( \text{CO} \) at equilibrium is: \[ p = 500 \text{ torr} \] - The pressure of \( \text{Cl}_2 \) at equilibrium is: \[ p = 500 \text{ torr} \] ### Step 6: Write the Expression for \( K_p \) The expression for the equilibrium constant \( K_p \) is given by: \[ K_p = \frac{P_{\text{CO}} \cdot P_{\text{Cl}_2}}{P_{\text{COCl}_2}} \] Substituting the equilibrium pressures: \[ K_p = \frac{(500)(500)}{500} = \frac{250000}{500} = 500 \] ### Final Answer Thus, the value of \( K_p \) is **500**. ---
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