The correct representation for the `K_(sp)` of `SnS_2` is

Options

A. `[Sn^(2+)][S^(2-)]^2`
B. `[Sn^(4+)][S^(-2)]^2`
C. `[Sn^(2+)][2S^(-2)]^2`
D. `[Sn^(4+)][2S^(2-)]^2`

Answer

To determine the correct representation for the solubility product constant \( K_{sp} \) of tin(IV) sulfide (\( SnS_2 \)), we follow these steps:

### Step 1: Understand the Dissolution Reaction
The dissolution of tin(IV) sulfide in water can be represented by the following reaction:
\[ SnS_2 (s) \rightleftharpoons Sn^{4+} (aq) + 2 S^{2-} (aq) \]

### Step 2: Write the Expression for \( K_{sp} \)
The solubility product constant \( K_{sp} \) is defined as the product of the concentrations of the ions produced in the dissolution reaction, each raised to the power of their coefficients in the balanced equation. For the reaction above, we have:
\[ K_{sp} = [Sn^{4+}][S^{2-}]^2 \]

### Step 3: Identify the Correct Representation
From the expression derived, we can see that:
- The concentration of \( Sn^{4+} \) is raised to the power of 1 (since it has a coefficient of 1).
- The concentration of \( S^{2-} \) is raised to the power of 2 (since it has a coefficient of 2).

Thus, the correct representation for \( K_{sp} \) of \( SnS_2 \) is:
\[ K_{sp} = [Sn^{4+}][S^{2-}]^2 \]

### Conclusion
The correct representation for the \( K_{sp} \) of \( SnS_2 \) is:
\[ K_{sp} = [Sn^{4+}][S^{2-}]^2 \]

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