The number of peroxide linkages in `CrO_(5) " and " H_(2)SO_(5)` respectively are

Options

A. 1, 1
B. 2, 0
C. 2, 1
D. 1, 2

Answer

To determine the number of peroxide linkages in \( \text{CrO}_5 \) and \( \text{H}_2\text{SO}_5 \), we need to analyze the structures of these compounds and identify the presence of oxygen-oxygen bonds, which are characteristic of peroxide linkages.

### Step-by-Step Solution:

#### Step 1: Analyze \( \text{CrO}_5 \)

1. **Determine the oxidation state of chromium (\( \text{Cr} \))**:
- The formula for \( \text{CrO}_5 \) indicates that there are 5 oxygen atoms.
- Oxygen typically has an oxidation state of -2. Therefore, the total contribution from oxygen is \( 5 \times (-2) = -10 \).
- Let the oxidation state of chromium be \( x \). The equation can be set up as follows:
\[ x + (-10) = 0 \implies x = +10 \]
- However, chromium can only have a maximum oxidation state of +6. Thus, we need to consider the presence of peroxide linkages.

2. **Identify the structure**:
- In \( \text{CrO}_5 \), chromium forms bonds with oxygen. Given the oxidation state of +6 is the maximum, the structure must accommodate this.
- The structure of \( \text{CrO}_5 \) is known to have a butterfly shape with two peroxide linkages. Each peroxide linkage consists of an O-O bond.

3. **Count the peroxide linkages**:
- There are 2 O-O bonds in the structure of \( \text{CrO}_5 \).

#### Step 2: Analyze \( \text{H}_2\text{SO}_5 \)

1. **Determine the oxidation state of sulfur (\( \text{S} \))**:
- The formula for \( \text{H}_2\text{SO}_5 \) indicates that there are 5 oxygen atoms and 2 hydrogen atoms.
- The total contribution from oxygen is \( 5 \times (-2) = -10 \) and from hydrogen is \( 2 \times (+1) = +2 \).
- Let the oxidation state of sulfur be \( y \). The equation can be set up as follows:
\[ 2 + y + (-10) = 0 \implies y = +8 \]
- However, sulfur can only have a maximum oxidation state of +6. Thus, we need to consider the structure.

2. **Identify the structure**:
- The structure of \( \text{H}_2\text{SO}_5 \) includes one sulfur atom bonded to four oxygen atoms, with one of those oxygen atoms forming a peroxide linkage with another oxygen atom.
- The structure typically includes one O-O bond (peroxide linkage) and other bonds to oxygen.

3. **Count the peroxide linkages**:
- There is 1 O-O bond in the structure of \( \text{H}_2\text{SO}_5 \).

### Final Answer:
- The number of peroxide linkages in \( \text{CrO}_5 \) is **2**.
- The number of peroxide linkages in \( \text{H}_2\text{SO}_5 \) is **1**.

### Summary:
- \( \text{CrO}_5 \): 2 peroxide linkages
- \( \text{H}_2\text{SO}_5 \): 1 peroxide linkage