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Standard reduction potentials of the hal...

Standard reduction potentials of the half reactions are given below
`{:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):}`
The strongest oxidising and reducing agents respectively are

A

`F_(2)" and "l^(-)`

B

`Br_(2)" and "Cl^(-)`

C

`Cl_(2)" and "Br^(-)`

D

`Cl_(2)" and "l_(2)`

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The correct Answer is:
To determine the strongest oxidizing and reducing agents from the given standard reduction potentials, we can follow these steps: ### Step 1: Understand Standard Reduction Potentials Standard reduction potentials (E°) indicate the tendency of a species to gain electrons (be reduced). The higher the E° value, the stronger the oxidizing agent. Conversely, the lower the E° value, the stronger the reducing agent. ### Step 2: Identify the Highest and Lowest E° Values From the given half-reactions and their standard reduction potentials: - \( \text{F}_2(g) + 2e^- \rightarrow 2\text{F}^-(aq) \), \( E° = +2.85 \, \text{V} \) - \( \text{Cl}_2(g) + 2e^- \rightarrow 2\text{Cl}^-(aq) \), \( E° = +1.36 \, \text{V} \) - \( \text{Br}_2(l) + 2e^- \rightarrow 2\text{Br}^-(aq) \), \( E° = +1.06 \, \text{V} \) - \( \text{I}_2(s) + 2e^- \rightarrow 2\text{I}^-(aq) \), \( E° = +0.53 \, \text{V} \) ### Step 3: Determine the Strongest Oxidizing Agent The strongest oxidizing agent corresponds to the half-reaction with the highest E° value. Here, \( \text{F}_2 \) has the highest E° value of +2.85 V, making it the strongest oxidizing agent. ### Step 4: Determine the Strongest Reducing Agent The strongest reducing agent corresponds to the half-reaction with the lowest E° value. Here, \( \text{I}^- \) (from the half-reaction involving \( \text{I}_2 \)) has the lowest E° value of +0.53 V, making it the strongest reducing agent. ### Conclusion Thus, the strongest oxidizing agent is \( \text{F}_2 \) and the strongest reducing agent is \( \text{I}^- \). ### Final Answer - Strongest oxidizing agent: \( \text{F}_2 \) - Strongest reducing agent: \( \text{I}^- \) ---
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Standard reduction potentails of the half reactions are given below: F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87 Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V The strongest oxidizing and reducing agents respectively are:

Standrd reduction potentials of the half reactions are given below : F_2 (g) +re^- rarr 2 F^(-) (aq) E^@ = + 2.85 V Cl_2 (g) +2e^- rarr 2 Cl^-(aq) , E^2 = + 1.36 V Br _2 (i) + 2 e^- rarr 2Br (aq) , E^2 = + 1. 06 V I_2 (s) + 2 e^- rarr 2I^(-) (aq) , E^2 = + . 53 V . The strongest oxidizing and reducing agents respectively

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