Home
Class 12
CHEMISTRY
In a crystalline solid, anions Y are arr...

In a crystalline solid, anions Y are arranged in ccp arrangement. Cations 'X' are equally distributed between tetrahedral and Octahedral voids. If all the octahedral voids are occupied, what is the formula of solid ?

Text Solution

Verified by Experts

Anions y in ccp arrangement = 4
Number of Octahedral voids = 4
Number of Tetrahedral voids = 4
Cations x in Octahedral voids = 4
Cations x in Tetrahedral voids = 4
`therefore` Total cations x in tetrahedral void and octahedral void = 8
`therefore x : y`
8 : 4
Hence, formula is `x_(2)y`
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-A (OBJECTIVE)|50 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-B (OBJECTIVE)|27 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise Assignment (SECTION - D) (ASSERTION-REASON TYPE QUESTION)|20 Videos

  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE|Exercise Assignment (Section-J)|10 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

In a crystalline solid, anions Y^(-) are arranged in ccp. Cation X^(+) are equally distributed between octehedral and tetrahedral voids. If all the octahedral voids are occupied, what is the formula of the compound ?

In a crystalline solid, anions B are arranged in ccp structure. Cations A are equally distributed between octahedral and tetrahedral voids if all the octahedral voids are occupied the formula of the ionic solids will be

In a crystalline solid anions B are arranged in cubic close packing. Cation A are equally distributed between octahedral and tetrahedral voids. If all the octahedral voids are occupied, the formula for the solid is

In a crystalline solid, anions B are arranged in a ccp. Cations A are equally distributed between octahedral and tetrahedral voids. If all the octahedral voids are occupied, the formula of the compound is A_2B//A_3B .

How will you distinguish between Tetrahedral and Octahedral voids ?

In a crystallizes solid, anions B are arranged in cubic close packing, cations A are equally distributed between octahedral and tetrahedral voids, what is the formula of the solid?

In a compound XY_(2) O_(4) , oxide ions are arranged in CCP and cations X are present in octahedral voids. Cations Y are equally distributed between octahedral and tetrahedral voids. The fraction of the octahedral voids occupied is :-

Octahedral void at edge centre in ccp arrangement is equally distributed among

AAKASH INSTITUTE-THE SOLID STATE -Try Yourself
  1. Three atoms P, Q & R crystallize in a cubic solid lattice having P ato...

    Text Solution

    |

  2. Calculate the approximate number of unit cells present in 1 g of gold....

    Text Solution

    |

  3. Elements A and B crystallize in cubic structure where atoms A are at t...

    Text Solution

    |

  4. Three elements P, Q and R crystallise in a cubic solid lattice with P ...

    Text Solution

    |

  5. In corrundum, oxid ions are arranged in h.c.p. array and the aluminum ...

    Text Solution

    |

  6. In a compound atoms of element Y form ccp lattice and those of elemen...

    Text Solution

    |

  7. In a crystalline solid, anions Y are arranged in ccp arrangement. Cati...

    Text Solution

    |

  8. Calculate the number of atoms in a cubic based unit cell having one at...

    Text Solution

    |

  9. A compound formed by elements A and B has a cubic structure in which A...

    Text Solution

    |

  10. The radius of Na(+) is 95 pm and that of CI^(-)ions is 181 pm. Predict...

    Text Solution

    |

  11. If the radius of Br^(-) ion is 0.182 nn, how large can a cation be fit...

    Text Solution

    |

  12. A compound AB crystallizes in bcc lattice with unit edge length of 380...

    Text Solution

    |

  13. Tungsten has bcc lattice. Each edge of unit cell is 316 pm and density...

    Text Solution

    |

  14. The element chromium crystallises in a body centred cubic lattice whos...

    Text Solution

    |

  15. Formula mass of NaCl is 58.45g mol^(-1) and density of its pure form i...

    Text Solution

    |

  16. An element occurs in bcc structure with edge length of 288 pm. Its den...

    Text Solution

    |

  17. Thallium chloride TlCl crystallises in either a simple cubic lattice o...

    Text Solution

    |

  18. An element with atomic mass 60 having fcc structure has a density of 6...

    Text Solution

    |

  19. Analysis shows that a metal oxide has empirical formula M(0.98)O(1.00)...

    Text Solution

    |

  20. Analysis shows that nickel oxide has the formula Ni(0.98)O(1.00). What...

    Text Solution

    |