Tungsten has bcc lattice. Each edge of unit cell is 316 pm and density of metal is 19.35 g/cc. How many atoms are present in 50 g of the element ?

Explanation

To find the number of atoms present in 50 g of tungsten, we will use the given information about the body-centered cubic (BCC) lattice structure, the edge length of the unit cell, and the density of tungsten. Here is the step-by-step solution:

### Step 1: Convert the edge length from picometers to centimeters.
The edge length of the unit cell is given as 316 pm (picometers). We need to convert this to centimeters for consistency with the density units.

\[ \text{Edge length (a)} = 316 \, \text{pm} = 316 \times 10^{-12} \, \text{m} = 316 \times 10^{-10} \, \text{cm} \]
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