Formula mass of `NaCl` is `58.45g mol^(-1)` and density of its pure form is `2.167g cm^(-3)`. The average distance between adjacent sodium and chloride ions in the crystal is `2.814xx10^(-8)cm`. Calculate Avogadro constant.

Explanation

Given, `M = 58.5 " " rho = 2.167 g//cm^(-3)`
`a=2xx2.814xx10^(-8)cm = 5.628xx10^(-8)cm`
`N_(0) = ? " " Z = 4`
`therefore N_(0)=(Z xx M)/(rho xx a^(3))=(4xx58.5)/(2.167(5.628xx10^(-10))^(3))`
`N_(0)=6.02xx10^(23)` atoms