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Total number of octahedral voids present...

Total number of octahedral voids present per unit cell of ccp unit cell is

A

8

B

9

C

12

D

4

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The correct Answer is:
To find the total number of octahedral voids present per unit cell of a cubic close-packed (ccp) unit cell, we can follow these steps: ### Step 1: Understand the Structure of ccp Unit Cell The cubic close-packed (ccp) structure, also known as face-centered cubic (fcc), consists of atoms located at each of the corners and the centers of each face of the cube. ### Step 2: Identify the Locations of Octahedral Voids In a ccp unit cell, octahedral voids are formed in two main locations: 1. At the center of the unit cell (1 void). 2. At the edge centers of the cube (12 edges). ### Step 3: Calculate the Contribution of Edge Center Voids Each edge of the cube has an octahedral void located at its center. Since there are 12 edges in a cube, we have: - Total edge voids = 12 However, each edge void is shared among 4 adjacent unit cells. Therefore, the contribution of each edge void to the unit cell is: - Contribution per edge void = 1/4 Thus, the total contribution from the edge voids is: \[ \text{Total edge voids contribution} = 12 \times \frac{1}{4} = 3 \] ### Step 4: Calculate the Contribution of the Body Center Void There is 1 octahedral void located at the center of the unit cell. This void is not shared with any other unit cell, so its contribution is: - Contribution from body center void = 1 ### Step 5: Calculate the Total Number of Octahedral Voids Now, we can sum the contributions from both the edge voids and the body center void: \[ \text{Total octahedral voids} = \text{Total edge voids contribution} + \text{Contribution from body center void} \] \[ \text{Total octahedral voids} = 3 + 1 = 4 \] ### Final Answer The total number of octahedral voids present per unit cell of a ccp unit cell is **4**. ---
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Assertion :- (A) total number of octahedral voids present in unit cell of cubic close of each packing including the one that is present at the body centre . Is four . Reason :- ( R) Besides the body centre there is one octahedral void present at the centre of each of the six faces of the unit cell and each of which is shared between two adjeccent units cells.

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AAKASH INSTITUTE-THE SOLID STATE -EXERCISE
  1. The number of tetrahedral voids present on each body diagonal ccp unit...

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  2. Octahedral void at edge center in ccp arrangement is equally distribut...

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  3. Total number of octahedral voids present per unit cell of ccp unit cel...

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  4. The co-ordination number in 3D-hexagonal close packing is

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  5. The efficiency of packing in simple cubic unit cell is

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  6. 'A' has fcc arrangement, 'B' is present in 2//3^(rd) of tetrahedral vo...

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  7. Gold crystallises in ccp structure. The number of voids present in 197...

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  8. The correct relation for radius of atom and edge - length in case of f...

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  9. The type of void present at the centre of the ccp unit cell is

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  10. The ratio of atoms present per unit cell in bcc to that present in fcc...

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  11. Stoichiometric defect is also known as

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  12. Which one of the following compounds can show Frenkel defect ?

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  13. In NaCl there are schottky pairs per cm^(3) at room temperature

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  14. Which of the following compounds is likely to show both Frenkel a...

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  15. The anionic sites occupied by electrons are called

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  16. The solids which are good conductor of electricity should have conduct...

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  17. Identify the antiferromagnetic substance

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  18. n-type semiconductor is

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  19. Which of the following substance is diamagnetic ?

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  20. Metal excess defect arises due to

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