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A crystalline solid AB adopts sodium chl...

A crystalline solid AB adopts sodium chloride type structure with edge length of the unit cell as 745 pm and formula mass of 74.5 g The density of the crystalline compound is

A

`2.16 g cm^(-3)`

B

`0.99 g cm^(-3)`

C

`1.88 g cm^(-3)`

D

`1.197 g cm^(-3)`

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The correct Answer is:
To calculate the density of the crystalline solid AB that adopts a sodium chloride type structure, we can follow these steps: ### Step 1: Identify the parameters - **Edge length (a)** of the unit cell = 745 pm = 745 x 10^-10 cm - **Formula mass (M)** = 74.5 g/mol - **Number of atoms per unit cell (Z)** for NaCl structure = 4 ### Step 2: Convert edge length to centimeters We need to convert the edge length from picometers to centimeters: \[ a = 745 \, \text{pm} = 745 \times 10^{-12} \, \text{m} = 745 \times 10^{-10} \, \text{cm} \] ### Step 3: Calculate the volume of the unit cell The volume \( V \) of the cubic unit cell can be calculated using the formula: \[ V = a^3 \] Substituting the value of \( a \): \[ V = (745 \times 10^{-10} \, \text{cm})^3 \] \[ V = 4.14 \times 10^{-28} \, \text{cm}^3 \] ### Step 4: Calculate the mass of the unit cell The mass of the unit cell can be calculated using the formula: \[ \text{Mass of unit cell} = \frac{M}{N_A} \times Z \] Where \( N_A \) (Avogadro's number) = \( 6.022 \times 10^{23} \) mol^-1. Substituting the values: \[ \text{Mass of unit cell} = \frac{74.5 \, \text{g/mol}}{6.022 \times 10^{23} \, \text{mol}^{-1}} \times 4 \] \[ \text{Mass of unit cell} = \frac{74.5}{6.022 \times 10^{23}} \times 4 \] \[ \text{Mass of unit cell} \approx 4.94 \times 10^{-22} \, \text{g} \] ### Step 5: Calculate the density Density \( d \) can be calculated using the formula: \[ d = \frac{\text{Mass of unit cell}}{\text{Volume of unit cell}} \] Substituting the values: \[ d = \frac{4.94 \times 10^{-22} \, \text{g}}{4.14 \times 10^{-28} \, \text{cm}^3} \] \[ d \approx 1190.10 \, \text{g/cm}^3 \] \[ d \approx 1.19 \, \text{g/cm}^3 \] ### Final Answer The density of the crystalline compound AB is approximately **1.19 g/cm³**. ---
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AAKASH INSTITUTE-THE SOLID STATE -Assignment (SECTION - A) (OBJECTIVE TYPE QUESTION)
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  2. For face centered cubic structure edge length 'a' can be related with ...

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  3. A crystalline solid AB adopts sodium chloride type structure with edge...

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  4. If radius of an octahedral void is r and atomic radius of atoms assumi...

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  5. Polonium adopts cubic structure with edge length of cube being 0.336 n...

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  6. CsCl has bcc structure with Cs^(+) at the centre and Cl^(-) ion at eac...

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  7. Ice crystallises in hexagonal lattice having volume of unit cell is 13...

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  8. For tetrahedral co-ordination the radius ratio (r^(+) //r^(-))should b...

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  9. The radius of the Na^(+) is 95 pm and that of CI ion is 181 pm Predict...

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  10. Lithium metal has a body centred cubic structure. Its density is 0.53 ...

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  11. What is the volume of a face centred cubic unit cell, when its density...

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  12. The number of octahedral sites in a cubical close pack array of N sphe...

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  13. For a solid with the following structure, the coordination number of t...

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  14. The empty space between the shaded balls and hollow balls as shown in ...

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  15. A mineral having the formula AB(2), crystallises in the cubic close -p...

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  16. KF has NaCl type of structure. The edge length of its unit cell has be...

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  17. Which of the following features is false regarding the structure of Cs...

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  18. Which type of solids will have the highest melting point ?

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  19. The mass of unit cell of Na(2)O is

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  20. In normal spinel structure there is a closed packed array of O^(2-) io...

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