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In Freundlich adsorption isotherm, at mo...

In Freundlich adsorption isotherm, at moderate pressure extent of adsorption (x/m) directly proportional to `P^(x)` . The value of x is

A

1

B

Zero

C

`infty`

D

`(1)/(n)`

Text Solution

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The correct Answer is:
To solve the question regarding the Freundlich adsorption isotherm, we need to analyze the relationship between the extent of adsorption and pressure at moderate pressure conditions. ### Step-by-Step Solution: 1. **Understanding the Freundlich Adsorption Isotherm**: - The Freundlich adsorption isotherm describes how the extent of adsorption (x/m) varies with pressure (P) at constant temperature. - The general equation is given by: \[ \frac{x}{m} = k P^{\frac{1}{n}} \] where: - \( x \) = mass of adsorbate, - \( m \) = mass of adsorbent, - \( k \) = a constant, - \( P \) = pressure, - \( n \) = a constant (where \( n > 0 \)). 2. **Identifying the Relationship at Moderate Pressure**: - The problem states that at moderate pressure, the extent of adsorption \( \frac{x}{m} \) is directly proportional to \( P^x \). - This can be expressed mathematically as: \[ \frac{x}{m} \propto P^x \] 3. **Comparing the Two Expressions**: - From the Freundlich isotherm, we have: \[ \frac{x}{m} = k P^{\frac{1}{n}} \] - From the given condition, we have: \[ \frac{x}{m} \propto P^x \] - To find the value of \( x \), we can equate the exponents of \( P \) from both expressions: \[ \frac{1}{n} = x \] 4. **Conclusion**: - Thus, the value of \( x \) is: \[ x = \frac{1}{n} \] ### Final Answer: The value of \( x \) in the equation \( \frac{x}{m} \propto P^x \) at moderate pressure in the Freundlich adsorption isotherm is \( \frac{1}{n} \).
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