Home
Class 12
CHEMISTRY
0.185 g of an organic substance when tre...

0.185 g of an organic substance when treated with conc `HNO_(3)` gave 0.328 g of silver bromide. Calculate the % of bromine in the compound.

Text Solution

Verified by Experts

w=0.185 g
wt. og AgBr = 0.320 g
% og Br =`(80xx0.320xx100)/(180xx0.185)=73.60`
Promotional Banner

Topper's Solved these Questions

  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    AAKASH INSTITUTE|Exercise Try Yourself|23 Videos

  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    AAKASH INSTITUTE|Exercise Exercise|64 Videos

  • MOCK_TEST_20

    AAKASH INSTITUTE|Exercise EXAMPLE|28 Videos

  • ORGANIC CHEMISTRY: SOME BASIC PRINCIPLE AND TECHNIQUES

    AAKASH INSTITUTE|Exercise TRY YOURSELF|28 Videos

Similar Questions

Explore conceptually related problems

0.185 g of an organic substance when treated with conc HNO_(3) gave 0.32 g of silver bromide. Calculate the % of bromine in the compound.

Aniline when treated with conc. HNO_3 gives

When Sn is treated with conc. HNO_(3)

0.2595 gm of an organic substance when treated by carius method gave 0.35 gm of BaSO_4 . Calculate the percentage of sulphur in the compound?

0.2595 g of an organic substance, when treated by carius method gave 0.25g of BaSO_(4) calculates the % of S in the compound.

When chloroform is treated with conc HNO_(3) it gives