0.2g of an organic compound of kjedahl's analysis gave enough ammonia to just neutralise 20ml of 0.1 `N H_(2)SO_(4)` Calculate the % of nitrogen in the compound.

0.25g of an organic compound on Kjeldahl's analysis gave enough ammonia to just neutralise 10cm^(3) of 0.5 M H_(2)SO_(4) . The percentage of nitrogen in the compound is :

0.5g of an organic compound on Kjeldahl's analysis gave enough ammonia to just neutralize 10 cm^(3) of 1 M H_(2)SO_(4) . The percentage of nitrogen in the compound is

0.5g of organic compound in Kjeldhal's method liberated anumonia,which neutralised 60ml of 0.1NH_(2)SO_(4) solution.The percentage of nitrogen in the compound is

The ammonia evolved from 0.7g of the organic compound in Kjeldahl's estimation of nitrogen,neutralize 5mL of 1MH_(2)SO_(4) .The percentage of nitrogen in the compound is

In Kjeldahl's method used for estimation of nitrogen, ammonia evolved from 0.6g of ml sample of organic compound neutralised 20 ml of 1 N H_(2)SO_(4) . Then calculate % of nitrogen in that compound :

The ammonia evolved from 2 g of a compound in Kjeldahl's estimation of nitrogen neutralizes 10 mL of 2 M H_(2)SO_(4) solution. The weight percentage of nitrogen in the compound is :

During estimation of nitrogen present in an organic compound by Kjeldahl’s method, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M H_(2)SO_(4) . Find out the percentage of nitrogen in the compound.