If `cos^(-1).(6x)/(1 + 9x^(2)) = -(pi)/(2) + 2 tan^(-1) 3x`, then find the values of x

Explanation

`cos^(-1).(6x)/(1 + 9 x^(2)) = -(pi)/(2) + 2 tan^(-1) 3x`
`(pi)/(2) - sin^(-1).(6x)/(1 + 9x^(2)) = -(pi)/(2) + 2 tan^(-1) 3x`
`sin^(-1).(6x)/(1 + 9x^(2)) = pi - 2 tan^(-1) 3x`
`sin^(-1).(2 xx 3x)/(1 + (3x)^(2)) = pi - 2 tan^(-1) 3x`
It is true when `3x gt 1`
or `x gt (1)/(3)`
i.e., `x in ((1)/(3), oo)`