Correct set of quantum number for last electron of La (57):

Options

A. `n=5,l=2,m=0,s=+(1)/(2)`
B. `n=6,l=2,m=0,s=+(1)/(2)`
C. `n=6,l=3,m=1,s=-(1)/(2)`
D. `n=6,l=3,m=-2,s=+(1)/(2)`

Explanation

`La_(37)=[Xe]_(54)6s^(2)5d^(1)`
Last electron enter in 5g so n=5
l=2
m=any value from (-2 to +2) including zero
`s=+(1)/(2)` or `-(1)/(2)`