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For a pure liquid (Specific gravity 2) h...

For a pure liquid (Specific gravity 2) having molar mass 50gm/mol. Ratio of molarity to molality is:

A

20kg/litre

B

`(1)/(2)kg//litre`

C

200kg/litre

D

2000 kg/ `m^(3)`

Text Solution

Verified by Experts

For pure liq. Take 1 litre volume
`d=(2gm)/(ml)=("Mass of liquid")/(1000ml)rArr` Mass of liquid =200gm=2kg
`(M)/(m)=(n_("liq"))/(V("lit"))xx("Mass of solvent"(kg))/(n_(("liq")))=(2)/(1)kg//litre`
`=(2kg)/(10^(-3)m^(3))=2000kg//m^(2)`
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