Correct set of quantum number for last electron of Pd.

Options

A. `n=5,l=2,m=0,s=-(1)/(2)`
B. n=4,l=2,m=0,s=`-(1)/(2)`
C. n=4,l=0,m=0,s=`-(1)/(2)`
D. n=6,l=0,m=0,s=`+(1)/(4)`

Explanation

`Pd_(46)=[Kr]_(36)5s^(0)4d^(10)`
`n=4, l=2,m=0,s=-(1)/(2)`