For 500ml 22.4V `H_(2)O_(2)` solution having density 1.2 gm/ml. Identify correct statement(s)

Options

A. Molality =1.76m
B. `(W)/(W)%-5.66`
C. `(W)/(v)%=68%`
D. 11.2 litre of `O_(2)` will be evolved at NTP.

Explanation

`M_(H_(2)O_(2)) "solution"=('V')/(11.2)=(22.4)/(11.2)=2rArr` In 500 ml solution, `n_(H_(2)O_(2))=1, w_(H_(2)O_(2))=34gm`
`d_("solution")=1.2gm//ml=("Mass of solution")/(500)rArr` Mass of solution =600gm
Mass of solvent =600-34=566gm
(A) `m=(n_(H_(2)O_(2))xx1000)/(W_("water")(gm))=(1000)/(566)=1.76`
(B) `(W)/(W)%=(34)/(600)xx100=5.66%`
(C) `(W)/(v)%=(34)/(500)xx100=6.8%`
(D) 1 litre `H_(2)O_(2)` solution produce `O_(3)` (NTP) =22.4litre
`500 ml H_(2)O_(2)` solution produce `O_(2)(NTP)=11.2` litre