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Ammonia at a pressure of 10atm and CO(2)...

Ammonia at a pressure of 10atm and `CO_(2)` at a pressure of 20 atm are introduced into an evacuated chamber. If `K_(p)` for the reaction `NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g)` is 2020 `"atm"^(3)`, the total pressure after a long time is

A

less than 30 atm

B

more than 30atm

C

equal to 30atm

D

can't be predicted

Text Solution

Verified by Experts

Since there is no `NH_(2)COONH_(4)(s)` present in the chamber. Pressure will not change.
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Statement-1 : Ammonia at a pressure of 10 atm and CO_(2) at a pressure of 20 atm are intoduced into an evacuated chamber. If Kp for the reaction. NH_(2)COONH_(4)(s) 2NH_(3)(g) + CO_(2)(g) is 2020 atm^(3) , the total pressure after a long time is less than 30 atm. Statement-2 : Equilibrium can be attained from both directions.

NH_(3) at 10 atm and CO_(2) at 20 atm pressure are introduced in an evacuated chamber. If K_(p) for the reaction: NH_(2)COONH_(4)(s) hArr 2NH_(3) (g) +CO_(2)(g) is 2000 "atm"^(3) at 400K, then the final pressure in the reaction chamber will be:

The K_(p) of the reaction is NH_(4)HS_((s)) Leftrightarrow NH_(3(g))+H_(2)S_((g)) . If the total pressure at equilibrium is 30 atm.

The value of K_(P) for NH_(2)COONH_(4(s))hArr 2NH_(2(g))+CO_(2(g)) if the total prassure at equilibrium si P :-

For NH_(4)HS(s)hArr NH_(3)(g)+H_(2)S(g) If K_(p)=64atm^(2) , equilibrium pressure of mixture is

NH_(2)COONH_(2)(s) harr 2NH_(3)(g) + CO_(2)(g) If equilibrium pressure is 3 atm for the above reaction, K_(p) will be

Calculate K_(p) for the equilibrium, NH_(4)HS_((s))hArrNH_(3(g))+H_(2)S_((g)) if the total pressure inside reaction vessel s 1.12 atm at 105.^(@)C .

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