When heated, lithium reacts with nitrogen to gorm lithium nitride:
`Li(s)+N_(2)(g)rarrLi_(3)N_(s)`
When 21 gm of Li reacts with 280gm of `N_(2)` then 0.35 gm of `Li_(3)N` is formed. What is % yield of reaction.

3Mg(s)+N_(2)(g)toMg_(3)N_(2)

In the reaction 6Li+N_(2)rarr2Li_(3)N

27 gm of Al reacts with excess of oxygen to give 4.59 gm of Al_(2)O_(3) . Calculate percentage yield of reaction.

A : When C_(2) H_(5) - O- CH_(3) is reacted with oen mole of Hl then C_(2)H_(5)OH& CH_(3) l is formed . R : It is S_(N)1 reaction

Lithium metal reacts with nitrogen gas to produce a white solid Lithium nitride (Li_N) according to the reaction : 6 Li(s)+N_2 (s)to2Li_3N(s) if 8.4 g of Li is taken initially with excess of N_2(g) , then (Atomic weight of Li=7)

28gm lithium is fixed with 48gm O_(2) to react according to the following reaction Li + O_(2) rArr Li_(2)O The mass of Li_(2)O formed is:

28 gm lithium is mixed with 48 gm O_(2) to reacts according to the following reaction. 4Li + O_(2) to 2Li_(2)O The mass of Li_(2)O formed is

Li metal is one of the few substances that reacts directly with molecular nitrogen. The balanced equation for reaction is : 6Li(s)+N_(2)(g) rarr 2Li_(3)N(s) How many grams of the product, lithium nitride, can be prepared from 3.5g of lithium metal and 8.4 g of molecular nitrogen ? (Atomic weight Li = 7, N = 14)

Ammonia is produced in accordance with this equation . N_(2)(g) + 3H_(2)(g) rightarrow 2NH_(3)(g) In a particular experiment, 0.25mol of NH_(3) is formed when 0.5 mol of N_(2) is reacted with 0.5 mol of H_(2) . What is the percent yield?