Consider the following equilibrium
`H_(2)O(g)+CO(g)hArrH_(2)(g)+CO_(2)(g),K_(1)=2`
`FeO(s)+CO(g)hArrFe(s)+CO_(2)(g),K_(2)=4`
Then K for reaction:
`Fe(s)+H_(2)O(g)hArrFeO(s)+H_(2)(g)`

Options

A. 2
B. 1
C. `(1)/(3)`
D. `sqrt(2)`

Explanation

`H_(2)O(g)+CO(p)hArrH_(2)(g)+CO_(2)(g)`….(i)
`FeO(s)+CO(g)hArrFe(s)+CO_(2)(g)`…(ii)
Required reaction: `Fe(s)+H_(2)O(g)hArrFeO(s)+H_(2)(g)`…(iii)
Equation iii=Equation i-Equation ii
`K_(3)=(K_(1))/(K_(2))=(2)/(4)=(1)/(2)`