If magnitude of energy of electron in first Bohr orbit of hydrogen atom is x J and the Planck's constant is `6.625xx10^(-34)J` sec then what will be the expression of frequency of revolution of electrion in 3rd Bohr orbit of `He^(+)`.

Options

A. `(8x)/(27xx6.625xx10^(-34))Hz`
B. `(2x)/(27xx6.625xx10^(-34))Hz`
C. `(2x)/(2xx6.625xx10^(-34))Hz`
D. `(8x)/(3xx6.625xx10^(-34))Hz`

Explanation

Frequency of revolution `=(v)/(2pir)=((1)/(2)mv^(2))/(mvrpi)`
`((Z^(2))/(n^(2))x)/((nh)/(2))=(2xxZ^(2))/(n^(3))(x)/(h)`