Consider three flasks in diagram below. Assuming that connecting tube has negligible volume and all three falsks are at same temperature.

If only 1 and 2 stopcocks are opened then select correct option(s).

Options

A. `P_(HCl)=(1)/(2)` atm
B. `P_(NH_(3))=0` atm
C. `P_(NH_(3))+P_(HCl)=(1)/(2)` atm
D. `P_(He)=5` atm

Explanation

`n_(HCl)=(PV)/(RT)=(2xx1)/(RT)`
`n_(NH_(3))=(PV)/(RT)=(1xx1)/(RT)`
`NH_(3)+HClrarrNH_(4)Cl(s)`
moles `(1)/(RT) (2)/(RT)`
`0 (1)/(RT)`
`n_(HCl)` remain after reaction =`(1)/(RT)`
For `HCl(g):-P_("new")(V+V)=nRT`
`P_("new")xx2=(1)/(RT)xxRT`
`(P_(HCl))_("final")=P_("new")=(1)/(2)atm=P_("total")`
`P_(NH_(3))=0(LR)`