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In ^^^ ABC, the bisector AD of A is pe...

In `^^^` ABC, the bisector AD of A is perpendicular to side BC (see Fig. 7.27). Show that `A B\ =\ A C`and `DeltaA B C`is isosceles

Text Solution

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`/_ABD and /_ACD`
`angleBAD=angleCAD`
AD=AD
`angleADB=angleADC=90^0`
`/_ABD cong /_ACD (ASA)`
AB=AC
BD=CD
`angleABD=angleACD`
...
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