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In a triangle locate a point in its int...

In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.

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Here, in ∆ABC, we can find the incentre of this triangle by drawing the angle bisectors of the interior angles of this triangle. I is the point where these angle bisectors are intersecting each other.
Therefore, I is the point which is equidistant from all the sides of `∆ABC` that is `IP = IQ = IP.`
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