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line l is the bisector of an angle /A\ ...

line l is the bisector of an angle `/_A\ a n d/_B`is any point on l. BP and BQ are perpendiculars from B to the arms of `/_A`. Show that:
(i) `DeltaA P B~=DeltaA Q B`
(ii) BP = BQ or B is equidistant from the arms of `/_A`

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Given: l is the bisector of an angle `∠A` and `BP ⊥ AP` and `BQ ⊥ AQ`
To Prove: `ΔAPB ≅ ΔAQB `and `BP = BQ`
i) We can show two triangles APB and AQB are congruent by using AAS congruency rule and then show that the corresponding parts of congruent triangles will be equal. ...
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